A ball is thrown...

[ROBOTOP]

A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.4 m/s at an angle of 25.0° above the horizontal.

Find the maximum height of the ball above the ground. _____m

Calculate the speed of the ball at the highest point in the trajectory._____. m/s

how would i go about doing this problem?? thank youuu

[avinash]

A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.4 m/s at an angle of 25.0° above the horizontal.
Find the maximum height of the ball above the ground. _____m

Solution:
vo = 20.4 m/s
= 25.0°
Let H = maximum height reached by the ball measured from the point of throw.

H = vo^2 sin^2()/(2g)
= 20.4^2 * sin^2(25.0)/(2*9.8)
= 3.8 m
Maximum height from ground = 1.1 + 3.8 = 4.9 m
Ans: 4.9 m

Calculate the speed of the ball at the highest point in the trajectory._____. m/s
Solution: At the highest point, v = vo cos(25.0°) = 20.4 m/s cos(25.0°) = 18.5 m/s
Ans: 18.5 m/s